1295. Find Numbers with Even Number of Digits

QUESTION:

Given an array nums of integers, return how many of them contain an even number of digits.

Example 1:

``````Input: nums = [12,345,2,6,7896]
Output: 2
Explanation:
12 contains 2 digits (even number of digits).
345 contains 3 digits (odd number of digits).
2 contains 1 digit (odd number of digits).
6 contains 1 digit (odd number of digits).
7896 contains 4 digits (even number of digits).
Therefore only 12 and 7896 contain an even number of digits.
``````

Example 2:

``````Input: nums = [555,901,482,1771]
Output: 1
Explanation:
Only 1771 contains an even number of digits.
``````

Constraints:

``````1 <= nums.length <= 500
1 <= nums[i] <= 10^5
``````

EXPLANATION:

1.将数字利用tostring方法转化成string
2.判断string的length，是否为偶数
3.循环到数组结尾

SOLUTION:

``````class Solution {
public int findNumbers(int[] nums) {
int result = 0;
for(int num: nums){
String num_str = Integer.toString(num);
if(num_str.length()%2==0) result++;
}
return result;
}
}
``````
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