#### QUESTION:

Given a m x n matrix grid which is sorted in non-increasing order both row-wise and column-wise, return the number of negative numbers in grid.

**Example 1:**

```
Input: grid = [[4,3,2,-1],[3,2,1,-1],[1,1,-1,-2],[-1,-1,-2,-3]]
Output: 8
Explanation: There are 8 negatives number in the matrix.
```

**Example 2:**

```
Input: grid = [[3,2],[1,0]]
Output: 0
```

**Constraints:**

```
m == grid.length
n == grid[i].length
1 <= m, n <= 100
-100 <= grid[i][j] <= 100
```

#### EXPLANATION:

easy的题目，for循环嵌套遍历就可以

#### SOLUTION:

```
class Solution {
func countNegatives(_ grid: [[Int]]) -> Int {
var result:Int = 0
for gri in grid {
for gr in gri {
if gr < 0 {
result += 1
}
}
}
return result
}
}
```