#### QUESTION:

Given the array candies and the integer extraCandies, where candies[i] represents the number of candies that the ith kid has.

For each kid check if there is a way to distribute extraCandies among the kids such that he or she can have the greatest number of candies among them. Notice that multiple kids can have the greatest number of candies.

Example 1:

```
Input: candies = [2,3,5,1,3], extraCandies = 3
Output: [true,true,true,false,true]
Explanation:
Kid 1 has 2 candies and if he or she receives all extra candies (3) will have 5 candies --- the greatest number of candies among the kids.
Kid 2 has 3 candies and if he or she receives at least 2 extra candies will have the greatest number of candies among the kids.
Kid 3 has 5 candies and this is already the greatest number of candies among the kids.
Kid 4 has 1 candy and even if he or she receives all extra candies will only have 4 candies.
Kid 5 has 3 candies and if he or she receives at least 2 extra candies will have the greatest number of candies among the kids.
```

Example 2:

```
Input: candies = [4,2,1,1,2], extraCandies = 1
Output: [true,false,false,false,false]
Explanation: There is only 1 extra candy, therefore only kid 1 will have the greatest number of candies among the kids regardless of who takes the extra candy.
```

Example 3:

```
Input: candies = [12,1,12], extraCandies = 10
Output: [true,false,true]
```

Constraints:

```
2 <= candies.length <= 100
1 <= candies[i] <= 100
1 <= extraCandies <= 50
```

#### EXPLANATION:

题意很简单分成两步

1.首先找到最大的那个值

2.再按顺序将每个孩子拥有的加上extra的和最大的那个做对比

3.如果大于等于最大值，就添加true，否则就添加false

#### SOLUTION:

```
class Solution {
public List<Boolean> kidsWithCandies(int[] candies, int extraCandies) {
int max = IntStream.of(candies).max().getAsInt();
ArrayList<Boolean> result = new ArrayList<>();
IntStream.of(candies).forEach(a -> {
if(a+extraCandies < max) result.add(false);
else result.add(true);
});
return result;
}
}
```