#### QUESTION:

You are given an array of unique integers salary where salary[i] is the salary of the ith employee.

Return the average salary of employees excluding the minimum and maximum salary. Answers within 10-5 of the actual answer will be accepted.

**Example 1:**

```
Input: salary = [4000,3000,1000,2000]
Output: 2500.00000
Explanation: Minimum salary and maximum salary are 1000 and 4000 respectively.
Average salary excluding minimum and maximum salary is (2000+3000) / 2 = 2500
```

**Example 2:**

```
Input: salary = [1000,2000,3000]
Output: 2000.00000
Explanation: Minimum salary and maximum salary are 1000 and 3000 respectively.
Average salary excluding minimum and maximum salary is (2000) / 1 = 2000
```

**Constraints:**

```
3 <= salary.length <= 100
1000 <= salary[i] <= 106
All the integers of salary are unique.
```

#### EXPLANATION:

这道题目就比较简单了, 直接用流操作即可.一行代码就可以搞定.

#### SOLUTION:

```
class Solution {
fun average(salary: IntArray): Double {
return salary.filter { it -> it != salary.min() && it != salary.max() }.average()
}
}
```