2169. Count Operations to Obtain Zero

#### QUESTION:

You are given two non-negative integers num1 and num2.

In one operation, if num1 >= num2, you must subtract num2 from num1, otherwise subtract num1 from num2.

For example, if num1 = 5 and num2 = 4, subtract num2 from num1, thus obtaining num1 = 1 and num2 = 4. However, if num1 = 4 and num2 = 5, after one operation, num1 = 4 and num2 = 1. Return the number of operations required to make either num1 = 0 or num2 = 0.

Example 1:

``````Input: num1 = 2, num2 = 3
Output: 3
Explanation:
- Operation 1: num1 = 2, num2 = 3. Since num1 < num2, we subtract num1 from num2 and get num1 = 2, num2 = 3 - 2 = 1.
- Operation 2: num1 = 2, num2 = 1. Since num1 > num2, we subtract num2 from num1.
- Operation 3: num1 = 1, num2 = 1. Since num1 == num2, we subtract num2 from num1.
Now num1 = 0 and num2 = 1. Since num1 == 0, we do not need to perform any further operations.
So the total number of operations required is 3.
``````

Example 2:

``````Input: num1 = 10, num2 = 10
Output: 1
Explanation:
- Operation 1: num1 = 10, num2 = 10. Since num1 == num2, we subtract num2 from num1 and get num1 = 10 - 10 = 0.
Now num1 = 0 and num2 = 10. Since num1 == 0, we are done.
So the total number of operations required is 1.
``````

Constraints:

``````0 <= num1, num2 <= 10^5
``````

#### EXPLANATION:

easy的题目, 比较简单, 按着题目给的模拟出来即可

#### SOLUTION:

``````class Solution {
func countOperations(_ num1: Int, _ num2: Int) -> Int {
var result:Int = 0
var numA = num1
var numB = num2
while numA != 0 && numB != 0 {
if numA >= numB {
numA = numA - numB
} else {
numB = numB - numA
}
result+=1
}
return result
}
}
``````
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