2347. Best Poker Hand

#### QUESTION:

You are given an integer array ranks and a character array suits. You have 5 cards where the ith card has a rank of ranks[i] and a suit of suits[i].

The following are the types of poker hands you can make from best to worst:

“Flush”: Five cards of the same suit. “Three of a Kind”: Three cards of the same rank. “Pair”: Two cards of the same rank. “High Card”: Any single card. Return a string representing the best type of poker hand you can make with the given cards.

Note that the return values are case-sensitive.

Example 1:

``````Input: ranks = [13,2,3,1,9], suits = ["a","a","a","a","a"]
Output: "Flush"
Explanation: The hand with all the cards consists of 5 cards with the same suit, so we have a "Flush".
``````

Example 2:

``````Input: ranks = [4,4,2,4,4], suits = ["d","a","a","b","c"]
Output: "Three of a Kind"
Explanation: The hand with the first, second, and fourth card consists of 3 cards with the same rank, so we have a "Three of a Kind".
Note that we could also make a "Pair" hand but "Three of a Kind" is a better hand.
Also note that other cards could be used to make the "Three of a Kind" hand.
``````

Example 3:

``````Input: ranks = [10,10,2,12,9], suits = ["a","b","c","a","d"]
Output: "Pair"
Explanation: The hand with the first and second card consists of 2 cards with the same rank, so we have a "Pair".
Note that we cannot make a "Flush" or a "Three of a Kind".
``````

Constraints:

``````ranks.length == suits.length == 5
1 <= ranks[i] <= 13
'a' <= suits[i] <= 'd'
No two cards have the same rank and suit.
``````

#### SOLUTION:

``````class Solution {
func bestHand(_ ranks: [Int], _ suits: [Character]) -> String {
if (Set(suits).count == 1) {
return "Flush"
}
var countArr:[Int] = []
ranks.forEach({ rank in
countArr.append(ranks.filter{\$0 == rank}.count)
})
if (countArr.max()! >= 3) {
return "Three of a Kind"
}
if (countArr.max()! >= 2) {
return "Pair"
}
return "High Card"
}
}
``````
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