703. Kth Largest Element in a Stream

#### QUESTION:

Design a class to find the kth largest element in a stream. Note that it is the kth largest element in the sorted order, not the kth distinct element.

Your KthLargest class will have a constructor which accepts an integer k and an integer array nums, which contains initial elements from the stream. For each call to the method KthLargest.add, return the element representing the kth largest element in the stream.

Example:

int k = 3; int[] arr = [4,5,8,2]; KthLargest kthLargest = new KthLargest(3, arr); kthLargest.add(3); // returns 4 kthLargest.add(5); // returns 5 kthLargest.add(10); // returns 5 kthLargest.add(9); // returns 8 kthLargest.add(4); // returns 8 Note: You may assume that nums’ length ≥ k-1 and k ≥ 1.

#### SOLUTION:

``````class KthLargest {

ArrayList<Integer> list  = new ArrayList<>();

int k;

public KthLargest(int k, int[] nums) {
Arrays.sort(nums);
this.k = k;
}

public int add(int val) {
return list.get(list.size()-k);
}

private int binarySearch(int val){
int start = 0;
int end = list.size()-1;
while (start<=end){
int mid = (start+end)/2;
if(list.get(mid)==val) return mid;
else if(list.get(mid)>val) end = mid-1;
else start = mid+1;
}
return start;
}
}
``````
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