1217. Play with Chips

#### QUESTION:

There are some chips, and the i-th chip is at position chips[i].

You can perform any of the two following types of moves any number of times (possibly zero) on any chip:

Move the i-th chip by 2 units to the left or to the right with a cost of 0. Move the i-th chip by 1 unit to the left or to the right with a cost of 1. There can be two or more chips at the same position initially.

Return the minimum cost needed to move all the chips to the same position (any position).

Example 1:

Input: chips = [1,2,3] Output: 1 Explanation: Second chip will be moved to positon 3 with cost 1. First chip will be moved to position 3 with cost 0. Total cost is 1. Example 2:

Input: chips = [2,2,2,3,3] Output: 2 Explanation: Both fourth and fifth chip will be moved to position two with cost 1. Total minimum cost will be 2.

Constraints:

1 <= chips.length <= 100 1 <= chips[i] <= 10^9

#### EXPLANATION:

1.创建一个长度为2的数组来记录奇数和偶数的个数
2.返回两者个数中比较小的那个

#### SOLUTION:

``````    public static int minCostToMoveChips(int[] chips) {
int[] tmp = new int[2];
for(int chip:chips) tmp[chip%2]++;
return Math.min(tmp[0],tmp[1]);
}
``````