QUESTION:
Given two integer arrays arr1 and arr2, and the integer d, return the distance value between the two arrays.
The distance value is defined as the number of elements arr1[i] such that there is not any element arr2[j] where | arr1[i]-arr2[j] | <= d. |
Example 1:
Input: arr1 = [4,5,8], arr2 = [10,9,1,8], d = 2
Output: 2
Explanation:
For arr1[0]=4 we have:
|4-10|=6 > d=2
|4-9|=5 > d=2
|4-1|=3 > d=2
|4-8|=4 > d=2
For arr1[1]=5 we have:
|5-10|=5 > d=2
|5-9|=4 > d=2
|5-1|=4 > d=2
|5-8|=3 > d=2
For arr1[2]=8 we have:
|8-10|=2 <= d=2
|8-9|=1 <= d=2
|8-1|=7 > d=2
|8-8|=0 <= d=2
Example 2:
Input: arr1 = [1,4,2,3], arr2 = [-4,-3,6,10,20,30], d = 3
Output: 2
Example 3:
Input: arr1 = [2,1,100,3], arr2 = [-5,-2,10,-3,7], d = 6
Output: 1
Constraints:
1 <= arr1.length, arr2.length <= 500
-1000 <= arr1[i], arr2[j] <= 1000
0 <= d <= 100
EXPLANATION:
这个就比较简单了, 两个for循环的嵌套即可.
SOLUTION:
class Solution {
func findTheDistanceValue(_ arr1: [Int], _ arr2: [Int], _ d: Int) -> Int {
var result = 0
for arri in arr1 {
var flag: Bool = true
for arrj in arr2 {
if (abs(arrj - arri) <= d) {
flag = false
break
}
}
if (flag) {
result += 1
}
}
return result
}
}