QUESTION:
Given a string s of zeros and ones, return the maximum score after splitting the string into two non-empty substrings (i.e. left substring and right substring).
The score after splitting a string is the number of zeros in the left substring plus the number of ones in the right substring.
Example 1:
Input: s = "011101"
Output: 5
Explanation:
All possible ways of splitting s into two non-empty substrings are:
left = "0" and right = "11101", score = 1 + 4 = 5
left = "01" and right = "1101", score = 1 + 3 = 4
left = "011" and right = "101", score = 1 + 2 = 3
left = "0111" and right = "01", score = 1 + 1 = 2
left = "01110" and right = "1", score = 2 + 1 = 3
Example 2:
Input: s = "00111"
Output: 5
Explanation: When left = "00" and right = "111", we get the maximum score = 2 + 3 = 5
Example 3:
Input: s = "1111"
Output: 3
Constraints:
2 <= s.length <= 500
The string s consists of characters '0' and '1' only.
EXPLANATION:
直接一个for循环即可解释出结果.
SOLUTION:
import kotlin.math.max
class Solution {
fun maxScore(s: String): Int {
var oneCount = s.count{ c -> c=='1' }
var zeroCount:Int = 0
var result:Int = 0
for (i in 0 until s.length-1) {
var it = s[i]
if (it == '0') {
zeroCount += 1
} else {
oneCount -= 1
}
result = max(result, zeroCount+oneCount)
}
return result
}
}