1773. Count Items Matching a Rule


You are given an array items, where each items[i] = [typei, colori, namei] describes the type, color, and name of the ith item. You are also given a rule represented by two strings, ruleKey and ruleValue.

The ith item is said to match the rule if one of the following is true:

ruleKey == “type” and ruleValue == typei. ruleKey == “color” and ruleValue == colori. ruleKey == “name” and ruleValue == namei. Return the number of items that match the given rule.

Example 1:

Input: items = [["phone","blue","pixel"],["computer","silver","lenovo"],["phone","gold","iphone"]], ruleKey = "color", ruleValue = "silver"
Output: 1
Explanation: There is only one item matching the given rule, which is ["computer","silver","lenovo"].

Example 2:

Input: items = [["phone","blue","pixel"],["computer","silver","phone"],["phone","gold","iphone"]], ruleKey = "type", ruleValue = "phone"
Output: 2
Explanation: There are only two items matching the given rule, which are ["phone","blue","pixel"] and ["phone","gold","iphone"]. Note that the item ["computer","silver","phone"] does not match.


1 <= items.length <= 104
1 <= typei.length, colori.length, namei.length, ruleValue.length <= 10
ruleKey is equal to either "type", "color", or "name".
All strings consist only of lowercase letters.


创建一个数组来判断type的位置. 再判断所在位置的值是否和ruleValue相同即可.


class Solution {
    fun countMatches(items: List<List<String>>, ruleKey: String, ruleValue: String): Int {
        var typeIndex = arrayOf("type","color","name")
        var result = 0
        for (item in items) {
            if (item.get(typeIndex.indexOf(ruleKey)).equals(ruleValue)) result++
        return result