1941. Check if All Characters Have Equal Number of Occurrences

#### QUESTION:

Given a string s, return true if s is a good string, or false otherwise.

A string s is good if all the characters that appear in s have the same number of occurrences (i.e., the same frequency).

Example 1:

``````Input: s = "abacbc"
Output: true
Explanation: The characters that appear in s are 'a', 'b', and 'c'. All characters occur 2 times in s.
``````

Example 2:

``````Input: s = "aaabb"
Output: false
Explanation: The characters that appear in s are 'a' and 'b'.
'a' occurs 3 times while 'b' occurs 2 times, which is not the same number of times.
``````

Constraints:

``````1 <= s.length <= 1000
s consists of lowercase English letters.
``````

#### EXPLANATION:

easy的题目, 一个for循环就可以了.

#### SOLUTION:

``````class Solution {
func areOccurrencesEqual(_ s: String) -> Bool {
var array:[Int] = Array(repeating: 0, count: 26)
var maxCount:Int = -1
for ch in s {
array[Int(ch.asciiValue! - 97)] += 1
maxCount = max(maxCount, array[Int(ch.asciiValue! - 97)])
}
var flag:Bool = true
for count in array {
if count != 0 && count != maxCount {
return false
}
}
return flag
}
}
``````