#### QUESTION:

There is a programming language with only four operations and one variable X:

++X and X++ increments the value of the variable X by 1. –X and X– decrements the value of the variable X by 1.

Initially, the value of X is 0.

Given an array of strings operations containing a list of operations, return the final value of X after performing all the operations.

**Example 1:**

```
Input: operations = ["--X","X++","X++"]
Output: 1
Explanation: The operations are performed as follows:
Initially, X = 0.
--X: X is decremented by 1, X = 0 - 1 = -1.
X++: X is incremented by 1, X = -1 + 1 = 0.
X++: X is incremented by 1, X = 0 + 1 = 1.
```

**Example 2:**

```
Input: operations = ["++X","++X","X++"]
Output: 3
Explanation: The operations are performed as follows:
Initially, X = 0.
++X: X is incremented by 1, X = 0 + 1 = 1.
++X: X is incremented by 1, X = 1 + 1 = 2.
X++: X is incremented by 1, X = 2 + 1 = 3.
```

**Example 3:**

```
Input: operations = ["X++","++X","--X","X--"]
Output: 0
Explanation: The operations are performed as follows:
Initially, X = 0.
X++: X is incremented by 1, X = 0 + 1 = 1.
++X: X is incremented by 1, X = 1 + 1 = 2.
--X: X is decremented by 1, X = 2 - 1 = 1.
X--: X is decremented by 1, X = 1 - 1 = 0.
```

**Constraints:**

```
1 <= operations.length <= 100
operations[i] will be either "++X", "X++", "--X", or "X--".
```

#### EXPLANATION:

很简单, 没有特别想说的.

#### SOLUTION:

```
class Solution {
func finalValueAfterOperations(_ operations: [String]) -> Int {
var result:Int = 0
for operation in operations {
if((operation == "X++") || (operation == "++X")) {
result+=1
} else if ((operation == "X--") || (operation == "--X")) {
result-=1
}
}
return result
}
}
```