QUESTION:
ou are given a 0-indexed integer array nums and a target element target.
A target index is an index i such that nums[i] == target.
Return a list of the target indices of nums after sorting nums in non-decreasing order. If there are no target indices, return an empty list. The returned list must be sorted in increasing order.
Example 1:
Input: nums = [1,2,5,2,3], target = 2
Output: [1,2]
Explanation: After sorting, nums is [1,2,2,3,5].
The indices where nums[i] == 2 are 1 and 2.
Example 2:
Input: nums = [1,2,5,2,3], target = 3
Output: [3]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 3 is 3.
Example 3:
Input: nums = [1,2,5,2,3], target = 5
Output: [4]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 5 is 4.
Constraints:
1 <= nums.length <= 100
1 <= nums[i], target <= 100
EXPLANATION:
一道easy的题目, 直接sort之后for循环判断即可.
SOLUTION:
class Solution {
func targetIndices(_ nums: [Int], _ target: Int) -> [Int] {
let arr = nums.sorted()
var result:[Int] = []
for index in arr.indices {
if arr[index]==target {
result.append(index)
}
}
return result
}
}