QUESTION:
Given an array of strings words, return the first palindromic string in the array. If there is no such string, return an empty string “”.
A string is palindromic if it reads the same forward and backward.
Example 1:
Input: words = ["abc","car","ada","racecar","cool"]
Output: "ada"
Explanation: The first string that is palindromic is "ada".
Note that "racecar" is also palindromic, but it is not the first.
Example 2:
Input: words = ["notapalindrome","racecar"]
Output: "racecar"
Explanation: The first and only string that is palindromic is "racecar".
Example 3:
Input: words = ["def","ghi"]
Output: ""
Explanation: There are no palindromic strings, so the empty string is returned.
Constraints:
1 <= words.length <= 100
1 <= words[i].length <= 100
words[i] consists only of lowercase English letters.
EXPLANATION:
这道题目就比较简单, 直接for循环拿出来进行reverse, 然后比对一下,如果结果相同, 那么就可以返回结果了.
SOLUTION:
class Solution {
func firstPalindrome(_ words: [String]) -> String {
var result:String = ""
for word in words {
let palindromic = word.reversed()
if String(palindromic)==word {
return word
}
}
return result
}
}