QUESTION:
You are given a string title consisting of one or more words separated by a single space, where each word consists of English letters. Capitalize the string by changing the capitalization of each word such that:
If the length of the word is 1 or 2 letters, change all letters to lowercase. Otherwise, change the first letter to uppercase and the remaining letters to lowercase. Return the capitalized title.
Example 1:
Input: title = "capiTalIze tHe titLe"
Output: "Capitalize The Title"
Explanation:
Since all the words have a length of at least 3, the first letter of each word is uppercase, and the remaining letters are lowercase.
Example 2:
Input: title = "First leTTeR of EACH Word"
Output: "First Letter of Each Word"
Explanation:
The word "of" has length 2, so it is all lowercase.
The remaining words have a length of at least 3, so the first letter of each remaining word is uppercase, and the remaining letters are lowercase.
Example 3:
Input: title = "i lOve leetcode"
Output: "i Love Leetcode"
Explanation:
The word "i" has length 1, so it is lowercase.
The remaining words have a length of at least 3, so the first letter of each remaining word is uppercase, and the remaining letters are lowercase.
Constraints:
1 <= title.length <= 100
title consists of words separated by a single space without any leading or trailing spaces.
Each word consists of uppercase and lowercase English letters and is non-empty.
EXPLANATION:
比较简单了, for循环之后进行判断, 如果小于或等于2, 那么就都改成小写, 否则就改成首字母大写. 存在一个arr里. 最后用join在一起, 用空格作为separator.
SOLUTION:
class Solution {
func capitalizeTitle(_ title: String) -> String {
var arr = title.split(separator: " ")
var result:[String] = []
for a in arr {
if a.count <= 2 {
result.append(a.lowercased())
} else {
result.append(a.capitalized)
}
}
return result.joined(separator: " ")
}
}