2133. Check if Every Row and Column Contains All Numbers

QUESTION:

An n x n matrix is valid if every row and every column contains all the integers from 1 to n (inclusive).

Given an n x n integer matrix matrix, return true if the matrix is valid. Otherwise, return false.

Example 1: 

Input: matrix = [[1,2,3],[3,1,2],[2,3,1]]
Output: true
Explanation: In this case, n = 3, and every row and column contains the numbers 1, 2, and 3.
Hence, we return true.

Example 2: 

Input: matrix = [[1,1,1],[1,2,3],[1,2,3]]
Output: false
Explanation: In this case, n = 3, but the first row and the first column do not contain the numbers 2 or 3.
Hence, we return false.

Constraints:

n == matrix.length == matrix[i].length
1 <= n <= 100
1 <= matrix[i][j] <= n

EXPLANATION:

首先想到的就是用set去比对count就行. 所以只要匹配出对应的colum和row即可.

SOLUTION:

class Solution {
    func checkValid(_ matrix: [[Int]]) -> Bool {
        for ma in matrix {
            if Set(ma).count != ma.count{
                return false
            }
        }
        for indexI in 0..<matrix.count {
            var tmpArr: [Int] = []
            for indexJ in 0..<matrix.count {
                tmpArr.append(matrix[indexJ][indexI])
            }
            if Set(tmpArr).count != matrix[indexI].count{
                return false
            }
        }
        return true

    }
}
--> return <--