QUESTION:
Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.
Example 1:
Input: s = "foobar", letter = "o"
Output: 33
Explanation:
The percentage of characters in s that equal the letter 'o' is 2 / 6 * 100% = 33% when rounded down, so we return 33.
Example 2:
Input: s = "jjjj", letter = "k"
Output: 0
Explanation:
The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.
Constraints:
1 <= s.length <= 100
s consists of lowercase English letters.
letter is a lowercase English letter.
EXPLANATION:
easy的题目, 直接取出相等的数量除以总数量即可.
SOLUTION:
class Solution {
func percentageLetter(_ s: String, _ letter: Character) -> Int {
var equal:Int = 0
for item in Array(s) {
if item == letter {
equal += 1
}
}
return equal * 100 / s.count
}
}