QUESTION:
You are given a sorted unique integer array nums.
Return the smallest sorted list of ranges that cover all the numbers in the array exactly. That is, each element of nums is covered by exactly one of the ranges, and there is no integer x such that x is in one of the ranges but not in nums.
Each range [a,b] in the list should be output as:
“a->b” if a != b “a” if a == b
Example 1:
Input: nums = [0,1,2,4,5,7]
Output: ["0->2","4->5","7"]
Explanation: The ranges are:
[0,2] --> "0->2"
[4,5] --> "4->5"
[7,7] --> "7"
Example 2:
Input: nums = [0,2,3,4,6,8,9]
Output: ["0","2->4","6","8->9"]
Explanation: The ranges are:
[0,0] --> "0"
[2,4] --> "2->4"
[6,6] --> "6"
[8,9] --> "8->9"
Constraints:
0 <= nums.length <= 20
-231 <= nums[i] <= 231 - 1
All the values of nums are unique.
nums is sorted in ascending order.
EXPLANATION:
一道easy的题目, 需要用两个指针来保存前后的位置. 其他的思路就比较简单了.
SOLUTION:
class Solution {
func summaryRanges(_ nums: [Int]) -> [String] {
if nums.count <= 0 {
return []
}
var result:[String] = []
var start:Int = nums[0]
var end:Int = nums[0]
if nums.count > 1 {
for index in 1...nums.count-1 {
if nums[index] - nums[index-1] == 1 {
continue
}
end = nums[index - 1]
if end == start {
result.append(start.description)
} else {
result.append(start.description + "->" + end.description)
}
start = nums[index]
}
}
end = nums[nums.count-1]
if end == start {
result.append(start.description)
} else {
result.append(start.description + "->" + end.description)
}
return result
}
}