2404. Most Frequent Even Element

QUESTION:

Given an integer array nums, return the most frequent even element.

If there is a tie, return the smallest one. If there is no such element, return -1.

Example 1:

``````Input: nums = [0,1,2,2,4,4,1]
Output: 2
Explanation:
The even elements are 0, 2, and 4. Of these, 2 and 4 appear the most.
We return the smallest one, which is 2.
``````

Example 2:

``````Input: nums = [4,4,4,9,2,4]
Output: 4
Explanation: 4 is the even element appears the most.
``````

Example 3:

``````Input: nums = [29,47,21,41,13,37,25,7]
Output: -1
Explanation: There is no even element.
``````

Constraints:

``````1 <= nums.length <= 2000
0 <= nums[i] <= 105
``````

SOLUTION:

``````class Solution {
func mostFrequentEven(_ nums: [Int]) -> Int {
var dic:Dictionary<Int,Int> = [:]
for num in nums where num % 2 == 0 {
dic[num] = dic[num, default: 0] + 1
}
return dic.sorted { a, b in
if a.value == b.value {
return a.key < b.key
} else {
return a.value > b.value
}
}.first?.key ?? -1
}
}
``````