2437. Number of Valid Clock Times

QUESTION:

You are given a string of length 5 called time, representing the current time on a digital clock in the format “hh:mm”. The earliest possible time is “00:00” and the latest possible time is “23:59”.

In the string time, the digits represented by the ? symbol are unknown, and must be replaced with a digit from 0 to 9.

Return an integer answer, the number of valid clock times that can be created by replacing every ? with a digit from 0 to 9.

Example 1:

Input: time = "?5:00"
Output: 2
Explanation: We can replace the ? with either a 0 or 1, producing "05:00" or "15:00". Note that we cannot replace it with a 2, since the time "25:00" is invalid. In total, we have two choices.

Example 2:

Input: time = "0?:0?"
Output: 100
Explanation: Each ? can be replaced by any digit from 0 to 9, so we have 100 total choices.

Example 3:

Input: time = "??:??"
Output: 1440
Explanation: There are 24 possible choices for the hours, and 60 possible choices for the minutes. In total, we have 24 * 60 = 1440 choices.

Constraints:

time is a valid string of length 5 in the format "hh:mm".
"00" <= hh <= "23"
"00" <= mm <= "59"
Some of the digits might be replaced with '?' and need to be replaced with digits from 0 to 9.

EXPLANATION:

easy的题目:
(??:mm) -> 24种情况
(?h:mm) -> 如果h是小于4, 那么有012三种情况, 否则就是2
(h?:mm) -> 如果h是2, 那么?就只有0,1,2,3这四种情况, 否则就是0-9都可以
(hh:mm) -> 这种只有1的情况了
分钟数就比较简单了.

SOLUTION:

class Solution {
    func countTime(_ time: String) -> Int {
        let array = Array(time)
        let h1 = array[0], h2 = array[1], m1 = array[3], m2 = array[4]

        let pattern: Int = {
            switch (h1, h2) {
            case ("?", "?"): return 24
            case ("?",   _): return (Int(String(h2))! < 4) ? 3 : 2
            case (  _, "?"): return (h1 == "2" ? 4 : 10)
            case (  _,   _): return 1
            }
        }()

        return pattern
             * (m1 == "?" ? 6 : 1)
             * (m2 == "?" ? 10 : 1)
    }
}
>
--> return <--