#### QUESTION:

Given two integers, num and t. A number is achievable if it can become equal to num after applying the following operation:

Increase or decrease the number by 1, and simultaneously increase or decrease num by 1. Return the maximum achievable number after applying the operation at most t times.

**Example 1:**

```
Input: num = 4, t = 1
Output: 6
```

**Explanation:**

Apply the following operation once to make the maximum achievable number equal to num:

Decrease the maximum achievable number by 1, and increase num by 1.
**Example 2:**

```
Input: num = 3, t = 2
Output: 7
```

**Explanation:**

Apply the following operation twice to make the maximum achievable number equal to num:

Decrease the maximum achievable number by 1, and increase num by 1.

**Constraints:**

```
1 <= num, t <= 50
```

#### EXPLANATION:

比较简单, 假设maxachievable是x, 那么对x减去t次, num加上t次. 就是最后的值. 也就是 x - t = num + t . 得到 x = num + t + t.

#### SOLUTION:

```
class Solution {
func theMaximumAchievableX(_ num: Int, _ t: Int) -> Int {
return num + (2 * t)
}
}
```