QUESTION:
You are given a 0-indexed array of strings words and a character x.
Return an array of indices representing the words that contain the character x.
Note that the returned array may be in any order.
Example 1:
Input: words = ["leet","code"], x = "e"
Output: [0,1]
Explanation: "e" occurs in both words: "leet", and "code". Hence, we return indices 0 and 1.
Example 2:
Input: words = ["abc","bcd","aaaa","cbc"], x = "a"
Output: [0,2]
Explanation: "a" occurs in "abc", and "aaaa". Hence, we return indices 0 and 2.
Example 3:
Input: words = ["abc","bcd","aaaa","cbc"], x = "z"
Output: []
Explanation: "z" does not occur in any of the words. Hence, we return an empty array.
Constraints:
1 <= words.length <= 50
1 <= words[i].length <= 50
x is a lowercase English letter.
words[i] consists only of lowercase English letters.
EXPLANATION:
一个for循环就可以搞定
SOLUTION:
class Solution {
func findWordsContaining(_ words: [String], _ x: Character) -> [Int] {
var result: [Int] = []
for i in 0..<words.count {
if words[i] .contains(x) {
result.append(i)
}
}
return result
}
}