QUESTION:
Given an array of strings strs, group the anagrams together. You can return the answer in any order.
An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.
Example 1:
Input: strs = ["eat","tea","tan","ate","nat","bat"]
Output: [["bat"],["nat","tan"],["ate","eat","tea"]]
Example 2:
Input: strs = [""]
Output: [[""]]
Example 3:
Input: strs = ["a"]
Output: [["a"]]
Constraints:
1 <= strs.length <= 104
0 <= strs[i].length <= 100
strs[i] consists of lowercase English letters.
EXPLANATION:
思路肯定就是, 首先将单个str进行排序, 再把排序结果当成key, 然后把对应的坐标当成value,进行保存, 这样就相当于对strs进行了排序. 最后再将排序后的dic展开成最后的结果即可.
SOLUTION:
class Solution {
func groupAnagrams(_ strs: [String]) -> [[String]] {
var dic: Dictionary<String, [Int]> = [:]
for (i, str) in strs.enumerated() {
dic[String(str.sorted()), default: []].append(i)
}
var result: [[String]] = []
for value in dic.values {
var tmpArr: [String] = []
for v in value {
tmpArr.append(strs[v])
}
result.append(tmpArr)
}
return result
}
}