QUESTION:
In a string S
of lowercase letters, these letters form consecutive groups of the same character.
For example, a string like S = "abbxxxxzyy"
has the groups "a"
, "bb"
, "xxxx"
, "z"
and "yy"
.
Call a group large if it has 3 or more characters. We would like the starting and ending positions of every large group.
The final answer should be in lexicographic order.
Example 1:
Input: "abbxxxxzzy"
Output: [[3,6]]
Explanation: "xxxx" is the single large group with starting 3 and ending positions 6.
Example 2:
Input: "abc"
Output: []
Explanation: We have "a","b" and "c" but no large group.
Example 3:
Input: "abcdddeeeeaabbbcd"
Output: [[3,5],[6,9],[12,14]]
Note: 1 <= S.length <= 1000
EXPLANATION:
只要把逻辑理清楚了就行:
1.首先把第一位拿出来 作为pre,同时记录位置。
2.将后面一位与前面比较,如果不同则进行位置比较,相同则重复该步骤
3.如果位置相隔3位,那么就添加在结果中。不超过3位就修改pre和标记位置
4.最后一个位置需要单独处理。因为最后不会有比较
SOLUTION:
class Solution {
public List<List<Integer>> largeGroupPositions(String S) {
char[] chars = S.toCharArray();
char pre = chars[0];
int index = 0;
ArrayList result = new ArrayList();
for(int i = 1;i<chars.length;i++){
if(chars[i]!=pre){
if(i-index>=3){
ArrayList tmp = new ArrayList<Integer>();
tmp.add(index);
tmp.add(i-1);
result.add(tmp);
}
pre = chars[i];
index=i;
}
}
if(chars.length-index>=3){
ArrayList tmp = new ArrayList<Integer>();
tmp.add(index);
tmp.add(chars.length-1);
result.add(tmp);
}
return result;
}
}