QUESTION:
Consider all the leaves of a binary tree. From left to right order, the values of those leaves form a leaf value sequence.
For example, in the given tree above, the leaf value sequence is (6, 7, 4, 9, 8)
.
Two binary trees are considered leaf-similar if their leaf value sequence is the same.
Return true
if and only if the two given trees with head nodes root1
and root2
are leaf-similar.
Note:
- Both of the given trees will have between
1
and100
nodes.
EXPLANATION:
看到题目就知道其实是一个中序遍历,但是要剔除不是leaf的节点。那么怎么才能算不是leaf的节点呢,就是node.left和node.right都不为null。
这样其实就可以了。
SOLUTION:
class Solution {
public boolean leafSimilar(TreeNode root1, TreeNode root2) {
ArrayList<Integer> values1 = new ArrayList<>();
ArrayList<Integer> values2 = new ArrayList<>();
leafSimilarHelper(root1,values1);
leafSimilarHelper(root2,values2);
for(int i = 0;i<values1.size();i++){
if(i<values2.size()){
if(values1.get(i)!=values2.get(i)) return false;
}else return false;
}
return true;
}
public static void leafSimilarHelper(TreeNode root,ArrayList list){
if(root == null) return;
leafSimilarHelper(root.left,list);
if(root.left==null && root.right==null) list.add(root.val);
leafSimilarHelper(root.right,list);
}
}