QUESTION:
Given a binary tree, return the inorder traversal of its nodes’ values.
For example:
Given binary tree [1,null,2,3]
,
1
\
2
/
3
return [1,3,2]
.
EXPLANATION:
二叉树的中序遍历,其实也没有什么好说的。
SOLUTION:
public class Solution {
public List<Integer> inorderTraversal(TreeNode root) {
ArrayList<Integer> result = new ArrayList<>();
inorderTraversalHelper(root,result);
return result;
}
public void inorderTraversalHelper(TreeNode root,ArrayList<Integer> set){
if(root==null) return;
inorderTraversalHelper(root.left,set);
set.add(root.val);
inorderTraversalHelper(root.right,set);
}
}