QUESTION:
Given two integers n and k, return all possible combinations of k numbers out of 1 … n.
For example, If n = 4 and k = 2, a solution is:
[
[2,4],
[3,4],
[2,3],
[1,2],
[1,3],
[1,4],
]
EXPLANATION:
这个依然是一个backtracking的问题,和之前的其实很一样
backtracking的公式是
if(someconditions)
result add
else
node.left
node.right
所以这个算法题就显而易见了,同时需要注意的是,这个循环只能往后进行循环,而不能一直重复循环。
SOLUTION:
class Solution {
public List<List<Integer>> combine(int n, int k) {
List<List<Integer>> result = new ArrayList<>();
List<Integer> subset = new ArrayList<>();
combineHelper(result,subset,n,k,1);
return result;
}
public void combineHelper(List<List<Integer>> result,List<Integer> subset,int n,int k,int start){
if(subset.size()==k){
result.add(new ArrayList<>(subset));
}else{
for(int i = start;i<=n;i++){
subset.add(i);
combineHelper(result,subset,n,k,i+1);
subset.remove(subset.size()-1);
}
}
}
}