537. Complex Number Multiplication

QUESTION:

Given two strings representing two complex numbers.

You need to return a string representing their multiplication. Note i2 = -1 according to the definition.

Example 1:

Input: "1+1i", "1+1i"
Output: "0+2i"
Explanation: (1 + i) * (1 + i) = 1 + i2 + 2 * i = 2i, and you need convert it to the form of 0+2i.

Example 2:

Input: "1+-1i", "1+-1i"
Output: "0+-2i"
Explanation: (1 - i) * (1 - i) = 1 + i2 - 2 * i = -2i, and you need convert it to the form of 0+-2i.

Note:

  1. The input strings will not have extra blank.
  2. The input strings will be given in the form of a+bi, where the integer a and b will both belong to the range of [-100, 100]. And the output should be also in this form.

EXPLANATION:

其实就是找出数据然后加减就可以。具体代码就在下面,也没有什么特别的。

SOLUTION:

public class Solution {
    public String complexNumberMultiply(String a, String b) {
        String[] result = a.split("\\+");
        int m = Integer.parseInt(result[0]);
        int n = Integer.parseInt(result[1].split("i")[0]);
        result = b.split("\\+");
        int x = Integer.parseInt(result[0]);
        int y = Integer.parseInt(result[1].split("i")[0]);
        int i = m*x + n*y*(-1);
        int j = m*y + n*x;
        return i+"+"+j+"i";
    }
}
>