QUESTION:
Given two strings representing two complex numbers.
You need to return a string representing their multiplication. Note i2 = -1 according to the definition.
Example 1:
Input: "1+1i", "1+1i"
Output: "0+2i"
Explanation: (1 + i) * (1 + i) = 1 + i2 + 2 * i = 2i, and you need convert it to the form of 0+2i.
Example 2:
Input: "1+-1i", "1+-1i"
Output: "0+-2i"
Explanation: (1 - i) * (1 - i) = 1 + i2 - 2 * i = -2i, and you need convert it to the form of 0+-2i.
Note:
- The input strings will not have extra blank.
- The input strings will be given in the form of a+bi, where the integer a and b will both belong to the range of [-100, 100]. And the output should be also in this form.
EXPLANATION:
其实就是找出数据然后加减就可以。具体代码就在下面,也没有什么特别的。
SOLUTION:
public class Solution {
public String complexNumberMultiply(String a, String b) {
String[] result = a.split("\\+");
int m = Integer.parseInt(result[0]);
int n = Integer.parseInt(result[1].split("i")[0]);
result = b.split("\\+");
int x = Integer.parseInt(result[0]);
int y = Integer.parseInt(result[1].split("i")[0]);
int i = m*x + n*y*(-1);
int j = m*y + n*x;
return i+"+"+j+"i";
}
}