QUESTION:
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
, return true.
Given "foo"
, "bar"
, return false.
Given "paper"
, "title"
, return true.
Note: You may assume both s and t have the same length.
EXPLANATION:
好吧,其实看代码就可以了,判断是否包含,不包含就添加,否则判断是否相等。
但是在不包含的时候还得判断该 值是否已经被其他的绑定,如果绑定了,那么就说明重复了。
直接就可以returnfalse。
SOLUTION:
public class Solution {
public boolean isIsomorphic(String s, String t) {
Hashtable<Character, Character> reflectTable = new Hashtable<>();
for (int i = 0; i < s.length(); i++) {
char key = s.charAt(i);
Object value = reflectTable.get(key);
if (value == null) {
char tValue = t.charAt(i);
boolean containValue = reflectTable.containsValue(tValue);
if(containValue)
return false;
reflectTable.put(key, t.charAt(i));
} else {
if ((char) value != t.charAt(i))
return false;
}
}
return true;
}
}