806. Number of Lines To Write String

#### QUESTION:

We are to write the letters of a given string `S`, from left to right into lines. Each line has maximum width 100 units, and if writing a letter would cause the width of the line to exceed 100 units, it is written on the next line. We are given an array `widths`, an array where widths is the width of ‘a’, widths is the width of ‘b’, …, and widths is the width of ‘z’.

Now answer two questions: how many lines have at least one character from `S`, and what is the width used by the last such line? Return your answer as an integer list of length 2.

``````Example :
Input:
widths = [10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10]
S = "abcdefghijklmnopqrstuvwxyz"
Output: [3, 60]
Explanation:
All letters have the same length of 10. To write all 26 letters,
we need two full lines and one line with 60 units.
``````
``````Example :
Input:
widths = [4,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10]
S = "bbbcccdddaaa"
Output: [2, 4]
Explanation:
All letters except 'a' have the same length of 10, and
"bbbcccdddaa" will cover 9 * 10 + 2 * 4 = 98 units.
For the last 'a', it is written on the second line because
there is only 2 units left in the first line.
So the answer is 2 lines, plus 4 units in the second line.
``````

Note:

• The length of `S` will be in the range [1, 1000].
• `S` will only contain lowercase letters.
• `widths` is an array of length `26`.
• `widths[i]` will be in the range of `[2, 10]`.

#### EXPLANATION:

1.首先每个字母代表的长度不一样，那得到每个字母的长度 widths[chars[i]=’a’]

2.然后累加，大于100的重新换行

3.换行就是行数加一，并且新行的unit已经是一个字符的长度了。

#### SOLUTION:

``````class Solution {
public int[] numberOfLines(int[] widths, String S) {
char[] chars = S.toCharArray();
int line = 1;
int count = 0;
for(int i = 0;i<chars.length;i++){
int len = widths[chars[i]-'a'];
count+=len;
if(count>100){
line++;
count=len;
}
}
return new int[]{line,count};
}
}
``````
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