QUESTION:
Given a non-negative integer represented as a non-empty array of digits, plus one to the integer.
You may assume the integer do not contain any leading zero, except the number 0 itself.
The digits are stored such that the most significant digit is at the head of the list.
EXPLANATION:
解题思路其实就是一位一位的相加,然后计算进位。
SOLUTION:
public class Solution {
public int[] plusOne(int[] digits) {
int carry = 0;
for(int i = digits.length-1;i>=0;i--){
int temp = digits[i];
if(i == digits.length-1)
temp+=1;
temp += carry;
carry = temp / 10;
temp = temp%10;
digits[i] = temp;
}
if(carry == 1){
int[] result = new int[digits.length+1];
result[0] = 1;
for(int i = 1 ; i < result.length;i++){
result[i] = digits[i-1];
}
return result;
}
return digits;
}
}