1. Two Sum

QUESTION:

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

EXPLANATION:

这个不用讲太多了，就是两个for循环，我倒是发现，之前的题目真的有点太简单了。反倒是那些最新的标为easy的反而是越来越难的，有很多奇怪的想法。

同时也发现最快的1ms的解答和这个答案是一样的，难道leetcode的判断逻辑还会和自己本地或者他服务端当时的性能有关？

SOLUTION:

public class Solution {
    public int[] twoSum(int[] nums, int target) {
        int[] result = new int[2];
        o:
        for (int i = 0; i < nums.length; i++) {
            for (int j = i + 1; j < nums.length; j++) {
                if (target-nums[i]==nums[j]){
                    result[0] = i;
                    result[1] = j;
                    break o;
                }
            }
        }
        return result;
    }
}
--> return <--